A can do the piece of work in 20 days which B can do in 12 days B worked at it for 9 days A can fini...........

Quant (SSC) Time and work

A can do the piece of work in 20 days which B can do in 12 days. B worked at it for 9 days. A can finish the remaining work in

5 days

7 days

11 days

3 days

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Explanation:

If A and B can do a work in x and y days respectively, and B leaves the work after doing for ‘a’ days then A does the remaining work in
[(y - a)x /y] days
Given:
Time taken by A = x = 20 days
Time taken by B = y = 12 days
Leaving time of work by B = a = 9 days
By the short trick approach,
A does the remaining work
= [(12 - 9) 20 /12] days
= 20/4 = 5 days