A construction company has 100 3 of its employees as women 50 of these women are married and 100 3 ...........

Quant (SSC) Time and work

A construction company has 100/3% of its employees as women. 50% of these women are married and 100/3% of married women have children. 75% of the men are married and 200/3% of married men have children. If no two employees are married to each other what fraction of the employees do not have children?

13/18

11/18

17/18

7/18

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Explanation:

Let 90 be the no. employees in the company
Therefore, total women employees = 90/3 = 30
{as 100/3% = 1/3}
As no. of women married = 50% of 30 = 15
No. of married women having children = 100/3% of 15 = 5
No. of married women not having children = 15 – 5 = 10
Now, total male employees = total – no. of women = 90 – 30 = 60
75% of men are married = 75% of 60 = 45
No. of married men having children
= 200/3% of 45 = 30
No. of married men not having children = 45 – 30 = 15
Now total married employees not having children in the company = no. of unmarried men and women + men and women not having children
= 15 + 15 + 10 + 15 = 55
Required fraction = 55/90 = 11/18