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The perimeters of two squares are 24 cm and 32 cm. The perimeter (in cm) of a third square of the area to the sum of the areas of these squares is
45
40
32
48
Side of square, whose perimeter is 24 cm = 24/4 = 6 cm So, area of square = 6^2 = 36
Again, side of square, whose perimeter is 32 cm = 32/4 = 8cm
So, area of this square = 8^2 = 64cm2
According to question, Area of new square
64 +36 = 100 cm2
side of the new square = √100 = 10
Hence perimeter of new square = 10 x 4 = 40 cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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