A train running at 7 11 of its own speed reached a place in 22 hours How much time could be saved if...........

Quantitative Aptitude ( CCS) Time & distance

A train running at 7/11 of its own speed reached a place in 22 hours. How much time could be saved if the train would run at its own speed?

14 hours

7 hours

8 hours

16 hours

The train ran at less than its full speed, which means it ran at a fraction of its full speed. This fraction is 7/11.

So, according to the question.

New speed = 7/11th of the usual speed

Then, new time = 11/7 of the usual time

So, 11/7 of usual time = 22 hours

Usual time = (22*7)/11

= 154/11 = 14 hours

Usual time is 14 hours and the time taken at less speed is 22 hours.

Hence, Time can be saved if the train would run at its usual speed

⇒ 22 - 14 = 8 hours.

Hence, option 3 is the correct answer.

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