If the average selling price of article II in shop A and B is Rs 3608 and that in shop B and C is Rs...........

Quantitative Aptitude ( CCS) Data Table

There are three shops A,B and C which sells different articles namely I , II III , IV and V respectively.the discount offered by each shops on different articles is given in the table.
NOTE: THE MARKED PRICE OF AN ARTICLE IS SAME IN ALL SHOPS

Articles	Disc. % by shop A	Disc. % by shop B	Disc. % by shop C
I	26%	28%	34%
II	14%	--	28%
II	--	12%	--
IV	26%	34%	--
V	--	--	24%

If the average selling price of article II in shop A and B is Rs. 3608 and that in shop B and C is Rs. 3300 , then the discount offered by shop B( in rupees) is ?

968

732

1734

862

1324

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Explanation:

Average selling price of article II by shop A and B is 3608 , so total selling price of both will be 7216

Writing in equation form :
Let “x “ be the market price which is same for all shops , discount rate of A for article II is 14 % , let “y “ be the discount rate for shop B
7216 = (100 - 14 /100) * X + (100 - Y /100) * X
7216 = x/100 * (86 + 100 - y)
7216 = x/100 * (186 - y).......(i)
Also ,
Average selling price of article II by shop B and C is 3300 , so total selling price of both will be 6600
Writing in equation form :
Let “x “ be the market price which is same for all shops , discount rate of C for article II is 28 % , let “y “ be the discount rate for shop B.
6600 = (100 - y /100) * X + (100 - 28 /100) * X
6600 = (100 - y /100) * X + 72x /100
6600 = x /100 * (172 - y).......(ii)
subtracting both equations, we get
616 = 14 * x/100
So market price = 4400
Discount offer by B can be found by substituting x in any one of the equation
Y = 22%
Disount amount = 4400 * 22 / 100
Discount amount = 968