In a 3 digit number unit 39 s digit is one more than the hundred 39 s digit and ten 39 s digit is on...........

Quantitative Aptitude ( CCS) Number System

In a 3-digit number, unit's digit is one more than the hundred's digit and ten's digit is one less than the hundred's digit. If the sum of the original 3-sigit number and numbers obtained by changing the order of digits cyclically is 2664, find the number

795

786

687

879

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Explanation:

let hundreds digit=x
thus tens digit=x-1
ones digit=x+1
the first form of our no. is x*100+(x-1)10+(x+1) =111x-9   (value no.1)
second form is
(x+1)100+x*10+(x-1)
= 111x+99       (value no 2)
third form is
(x-1)100+(x+1)10+(x)
=111x-90       (value no 3)

these three values add up to 2664
111x-9+111x+99+111x-90=2664
3(111x)=2664
111x=888
x=8
therefore our no is 8*100+(8-1)*10+(8+1) = 800+70+9 =879

Hence, option 4 is the correct answer.