What could be the maximum value of Q in the following equation 5P9 3R7 2Q8 1114 ........

Quantitative Aptitude ( CCS) Number System

What could be the maximum value of Q in the following equation? 5P9 + 3R7 + 2Q8 = 1114

The answer it 9. How to figure out the answer is to just do this.

(500+p0+9)+(300+R0+7)+(200+Q0+8) =1114
(1000+24)+(P+Q+R)10=1114,
P+Q+R=9

The max value of Q is 9, because to keep Q max P&R should be 0.

So P=0 Q=9 R=0

Hence, option 1 is the correct answer.

Submit Error

In the question the sum is114 instead of 1114 as explained in the answer.