A thief steals a car at 2 30 pm and drives it at 60 kmph The theft is discovered at 3 p m and the ow...........

Quantitative Aptitude ( CCS) Time & distance

A thief steals a car at 2.30 pm and drives it at 60 kmph. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 kmph. When will he overtake the thief?

4.30 pm

4.45 pm

5.00 pm

5.15 pm

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Explanation:

As Theft is discovered at 3:00pm but Thief stole the car at 2:30.
This means thief covered some distance in this 30 min gap.
Distance travelled by thief in 30 min = 60 * 1/2 = 30 km
Owner Discovered Car at 3:00pm
Now relative speed = (75-60)km/hr = 15km/hr
Time needed to travel 30km by the speed of 15km/hr.
Time at which owner meets thief = 30/15 = 2 hrs

So After 2 hrs (i.e,at 5:00 pm) the owner will catch/overtake the thief.

Hence, option 3 is the correct answer.