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A question paper has two parts, part A and part B, each containing 10 questions. If the student has to choose 8 from part A and 5 from part B, in how many ways can he choose the question?
11240
12240
13240
11340
There 10 questions in part A out of which 8 question can be chosen as = 10C8. Similarly, 5 questions can be chosen from 10 questions of Part B as = 10C5. Hence, total number of ways, =10C8*10C5 =[10!/(2!8!)]*[10!/(5!*5)] = {10*9/2}*{10*9*8*7*6/(5*4*3*2*1)} = 11340.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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