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The number of different six-digit numbers that are divisible by 10, which can be formed using the digits 1, 2, 7, 0, 9, 5?
100
120
140
160
Let the six digit number be abcdef 'a' can take all values except 0 since it will not be a 6 digit number then. So this means it can take any of 5 values. 'b' can take one the remaining 5 digits. 'c' can take any of the remaining 4 Similarly 'd' can take 3, 'e' can take 2 and 5'f' can take 1 value So this means the total numbers that can be formed are : 5*5*4*3*2*1 = 600 For the numbers divisible by 10: The last digit should be always 0 In this case the total possibilities are: 5*4*3*2*1*1 = 120
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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