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It is required to seat 5 men and 4 women in a row so that the women occupy the even places. How many such arrangements are possible?
2880
2480
3680
3280
According to the problem women will sit at the even places (2,4,6 and 8). They can be seated in P(4,4)=4!=24 ways Men will sit on the odd seats =(1,3,5,7 & 9 ways) They can sit on these seats in P(5,5)=5! ⇒5×4×3×2×1 ⇒120 ways If total number of ways P then P=24×120 =2880
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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