2ab5 is a four digit number divisible by 25 If the number formed from the two digits ab is a multipl...........

Quantitative Aptitude ( CCS) Number System

2ab5 is a four-digit number divisible by 25. If the number formed from the two digits ab is a multiple of 13, then ab =

We have given that the number 2ab5 is divisible by 25.

Any number divisible by 25 ends with the last two digits 00, 25, 50, or 75.
So, b5 should equal 25 or 75.

b=2 or 7.
Since a is now free to take any digit from 0 through 9, ab

can have multiple values.

We also have that ab is divisible by 13.
The multiples of 13 are 13,26,39,52,65,78 and 491

Among these, the only number ending with 2 or 7 is 52.

ab=52

Hence, option 4 is the correct answer.

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