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What is the maximum value of m such that 7m divides into 14! evenly?
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The term 14! equals the product of the numbers 1,2,3,4,5,6,7,8,9,10,11,12,13 and 14
Only two of these numbers are divisible by 7.
The numbers are 7 and 14.
Hence, 14! can be expressed as the product of k×7×14, where k is not divisible by 7.
Now, since there are two 7s in 14!, the numbers 7 and 72 divide 14! evenly
73 and further powers of 7 leave a remainder when divided into 14!.
Hence, the maximum value of m is 2.
Hence, option 2 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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