Find the lowest 4 digit number whichwhen divided by 3 4 or 5 leaves a remainder of 2 in each case ........

Quantitative Aptitude ( CCS) Number System

Download Solution PDF

Find the lowest 4-digit number whichwhen divided by 3, 4 or 5 leaves a remainder of 2 in each case?

1020

1026

1022

1030

छोटे Courses बड़े Results

Master Number System

Prepare through Micro-courses

Try Now

Explanation:

Lowest 4-digit number is 1000.
LCM of 3, 4 and 5
= 3, 4, 5
As we saw above no two numbers are divisible by common factor so their LCM is their product.
LCM of 3, 4 and 5 = 3 × 4 × 5 = 60.
Dividing 1000 by 60, we get the remainder 40. Thus, the lowest 4-digit number that exactly divisible by 3, 4 and 5 is 1000 + (60 - 40) = 1020.
Now, add the remainder 2 that's required. Thus, the answer is (1020 + 2 = 1022)