A 3 digit number 4a3 is added to another 3 digit number 984 to give a 4 dgist number 13b7 which is d...........

Quantitative Aptitude ( CCS) Number System

A 3-digit number 4a3 is added to another 3-digit number 984 to give a 4-dgist number 13b7, which is divisible by 11. Then, (a + b) = ?

4a3+984=13b7 which is divisible by 11.

We know that a number is divisible by 11 if the difference of sum of alternate digit is either 0 or multiple of 11.

The value of a can be 0,1or 2 as we can see and the value of b can be only 8 or 9.
By putting a=1
413+984=1397. Gives b= 9.

1397 is divisible by 11.

So a+b= 1+9=10.

Hence, option 1 is the correct answer.

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