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A two digit number when 18 added becomes another two digit number with reversed digits. How many such two digit numbers are possible?
12
11
7
9
Let the two digit number be 'ab' and the number formed after adding 18 to it is 'ba' So ab + 18 = ba ⇒ (10a + b) + 18 = 10b + a ⇒ 18 = 9b – 9a ⇒ 2 = b – a So we know that ab, ba both are two digit numbers so a, b ≠ 0. Also when b = 9, a = 7; b = 8, a = 6; b = 7, a = 5; b = 6, a = 4; b = 5, a = 3; b = 4, a = 2; b = 3, a = 1 Total 7 combinations are possible.
Hence, option 3 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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