Multiple Choice Questions on Three gold coins of weight 780gm 840gm and 960gm are cut into small pieces all of which have the equ........... for Mathematics - All Exams Preparation

Back to Main Page

Multiple Choice Questions

Three gold coins of weight 780gm 840gm and 960gm are cut into small pieces all of which have the equ...........

Quantitative Aptitude ( CCS) Simplification
    Download Solution PDF

    Three gold coins of weight 780gm, 840gm and 960gm are cut into small pieces, all of which have the equal weight. Each piece must be heavy as possible. If one such piece is shared by two persons, then how many persons are needed to give all the pieces of gold coins?

    86

    Correct Answer

    70

    Incorrect Answer

    43

    Incorrect Answer

    35

    Incorrect Answer
    छोटे Courses बड़े Results
    Master Simplification
    Prepare through Micro-courses
    Try Now
    Explanation:

    HCF(780,840,960) = 60

    Thus, total number of pieces:
    ⇒780/60 + 840/60 + 960/60

    = 13+14+16 = 43

    Total number of person required = 43×2 = 86.

    Hence, option 1 is the correct answer.

    By: Amit Kumar
    ProfileResources

    Let's Discuss

    Master
    Simplification
    With abhipedia
    Micro Courses
    Try Now
    What our students have to say
    Review on us
    Download Abhipedia Android App

    Access to prime resources

    Downlod from playstore
    download android app download android app for free