Let n be the number of different 5 digit numbers divisible by 4 with the digits 1 2 3 4 5 and 6 no d...........

Quantitative Aptitude ( CCS) Permutation & Combination

Let n be the number of different 5 digit numbers, divisible by 4 with the digits 1, 2, 3, 4, 5 and 6, no digit being repeated in the numbers

What is the value of n?

152

192

212

252

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Explanation:

Test of divisibility by 4 is that the last two digits should be divisible by 4.
Case 1 : When the last 2 digits are 12, i.e., _ _ _12=4×3×2=24 numbers
Case 2 : When the last 2 digits are 16, there are 24 numbers
Case 3 : When the last 2 digits are 24 there are 24 numbers
Case 4 : When the last 2 digits are 32 there are 24numbers
Case 5 : When last 2 digits are 36 there are 24 numbers
Case 6 : When last 2 digits are 52 there are 24 numbers
Case 7 : When last 2 digits are 56 there are 24 numbers
Case 8 : When last 2 digits are 64 there are 24 numbers
Total =8×24= 192

Hence, option 2 is the correct answer.