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In a 4000m race around a circular stadium having a circumference of 1000m, the fastest runner and the lowest runner reach teh same point at the end of the 5th minute, for the first time after the start of the race. All runners have he same starting point and each runner maintain a uniform speed throughout the race if the fastest runner runs at twice the speed of the slowest runner, what is the time taken by the fastest runner to finish the race?
20 min
15 min
10 min
5 min
Let speed of the slowest runner be x and fastest runner be 2x They will meet at the same point when the fastest runner runs one round extra when compared to the slowest runner. Relative speed of the fastest runner = 2x-x=x time = 5 minutes distance covered = 1000 metre Relative speed of the fastest runner = 1000/5 = 200 meter/minute Speed of the fastest runner = 200*2= 400 meter/minute Time taken by the fastest runner to finish the race = time taken by him to run 4000 km = 4000/400 = 10 minute
Hence, option is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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