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A test has 50 questions. A student scores 1 mark for a correct answer, –1/3 for a wrong answer, and –1/6 for not attempting a question. If the net score of a student is 32, the number of questions answered wrongly by that student cannot be less than
6
12
3
9
Let x be the number of questions answered correctly, and let y be the number of wrong answers. Then 50-x-y is the number of questions not attempted. The question seeks to find the smallest possible value of y. The score is x - y/3 - (50-x-y)/6 Let x be the number of questions answered correctly, and let y be the number of wrong answers. Then 50-x-y is the number of questions not attempted. The question seeks to find the smallest possible value of y. The score is x - y/3 - (50-x-y)/6 The score in this case is 32, so we have the equation 32 = x - y/3 - (50-x-y)/6 This simplifies to 32 = (7x-y-50)/6, and then we get 192 = 7x-y-50 242 = 7x-y y = 7x - 242 242 is more than 7*34, so x has to be at least 35, or else y is negative. So the smallest value of y occurs when x=35, and in that case, 7x - 242 is 3. So the smallest value of y or the smallest possible number of wrong answers is 3.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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