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A bag contains 2 blue balls, 3 green balls and 4 yellow balls. In how many ways can 3 balls be drawn from the bag, if at least one green ball is to be included in the draw?
32
64
128
256
From 2 blue balls, 3 green balls and 4 yellow balls, 3 balls are to be selected such that at least one green ball should be there. Hence we have 3 choices All three are green Two are green and one is non green One is green and two are non green Total number of ways = 3C3 + (3C2 x 6C1) + (3C1 x 6C2) [because 6 are non green] =1+ [3×6] + [3×15] = 1+18+45 = 64
By: Deepak Dawra ProfileResourcesReport error
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