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If Sushant rides his bicycle at the speed of 2 km/hr, he reaches his school late by 1 minute. On increasing the speed by 2 km/hr, he reaches 5 minute early. Can you find the distance between his school and his house?
400 km
360 km
480 km
300 km
If d is the required distance and T is the correct time,
Using distance = speed * time
d = 2 ( T +1/60) since he is late by 1/60 hour .
d = 4( T -5/60) since he is earlier by 5/60 hour.
2 ( T +1/60) = 4( T -5/60)
T = 11/60 hour
d = 2( 12/60) = 24/60 km = 0.4 km = 400 m
Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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