send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Sum of first 12 terms of a GP is equal to the sum of the first 14 terms in the same GP. Sum of the first 17 terms is 92, what is the third term in the GP?
92
-92
46
231
Sum of first 12 terms is equal to sum of first 14 terms. Sum of first 14 terms = Sum of first 12 terms + 13th term + 14th term => 13th term + 14th term = 0 Let us assume 13th term = k, common ratio = r. 14th term will be kr. k + kr = 0 k (1 + r) = 0 => r = -1 as k cannot be zero Common ratio = -1. Now, if the first term of this GP is a, second term would be -a, third would be a and so on The GP would be a, -a, a, -a, a, -a,... Sum to even number of terms = 0 Sum to odd number of terms = a Sum to 17 terms is 92 => a = 92 Third term = a = 92
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses