Two travelers set out on a long odyssey The first traveler starts from city X and travels north on a...........

Quantitative Aptitude ( CCS) Arithmetic progression

Two travelers set out on a long odyssey. The first traveler starts from city X and travels north on a certain day and covers 1 km on the first day and on subsequent days, he travels 2 km more than the previous day. After 3 days, a second traveler sets out from city X in the same direction as the first traveler and on his first day he travels 12 km and on subsequent days he travels 1 km more than the previous day. On how many days will the second traveler be ahead of the first?

2 days

6 days

From the 2nd day after the 2nd traveler starts

From the 3rd day after the 2nd traveler starts

छोटे Courses बड़े Results

Master Arithmetic progression

Prepare through Micro-courses

Try Now

Explanation:

Day 1: 1 km; Day 2: (1 + 2) = 3 km; Day 3: (1 + 2 + 2) = 5km and so on
i.e. on each of these days he covers the following distance Day 1: 1km, Day 2: 3km, Day 3: 5km and so on.
The distances covered each day by the first traveller is in an AP with the first term being 1 and the common difference being 2
After 3 days, the first traveler would have traveled 9 kms. He is ahead of the second traveler at the end of 3 days by 9 kms.