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Obtain the sum of all positive integers up to 1000, which are divisible by 5 and not divisible by 2.
70000
50000
14000
10000
The positive integers, which are divisible by 5, are 5, 10, 15, ..., 1000 Out of these 10,20,30,.... 1000 are divisible by 2 Thus, we have to find the sum of the positive integers 5, 15, 25, ...., 995 If n is the number of terms in it the sequence then 995 = 5 + 10(n - 1) => 1000 = 10n Therefore, n = 100. Thus the sum of the series = (n/2)(a + l) = (100/2) (5 + 995) = 50000.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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