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What is the sum of all two-digit numbers that give a remainder of 3 when they are divided by 7?
666
676
683
777
The two digit number which gives a remainder of 3 when divided by 7 are: 10, 17, 24 ..... 94. Now, these number are in AP series with 1st Term, a = 10; Number of Terms, n = 13; Last term, L = 94 and Common Difference, d = 7. = {n*(a+L)/2} = 13*52 = 676
Hence, option 2 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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