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If in a long division sum, the dividend in 380606 and the successive remainders from the first to the last are 434, 125 and 413, then divisor is
451
843
4215
3372
Let d = divisor and q = quotient First remove the last remainder: d x q + 413 = 380606 d x q = 380193 So d cannot be even (choice d) or a multiple of 5 (choice c). If we try choice a or b, a quick division (by calculator) shows that 380193 = 451 x 843, the other two choices. (In the absence of choices, we could find the prime factors of 380193, which are 3 x 11 x 41 x 281 and get various candidate divisors from that.) So one of them is the divisor and the other the quotient. So we can just check the first remainder: 843 x 4 = 3372 3806 - 3372 = 434 ... a match! And just to be sure: 451 x 8 = 3608 3806 - 3608 = 198 So the divisor is 843.
Hence, option 2 is the correct answer.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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