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An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.
25
64
50
27
12 = a + 2d 106 = a + 49d So, 106-12 = 47d Or, 94 = 47d So, d = 2 Hence, a = 8 And, n29 = 8 + 28*2 = 64.
By: Amit Kumar ProfileResourcesReport error
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