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The diameters of the internal and external surfaces of a hollow spherical shell are 10cm and 6 cm respectively. If it is melted and recasted into a solid cylinder of length 8/3 cm, find the diameter of the cylinder.
28√2 cm
14√2 cm
26√2 cm
18√2 cm
External diameter of a sphere = 10 cm Internal diameter of the sphere = 6 cm Volume of the sphere = 4/3 π (R3 – r3) = (4/3) (22/7) (103 – 63) = (4/3) (22/7) (784) = 9856 / 3 cm3 Height of the cylinder formed = 8/3 cm Let the radius of the cylinder be ‘r’ cm Volume of the cylinder = πr2h = 22/7 * r2 * 8/3 = 22/7 * r2 * 8/3 = 9856 / 3 r2 = 392 r = 14√2 cm So Diameter of the cylinder = 2 x 14√2 =28√2 cm
By: Amit Kumar ProfileResourcesReport error
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