A jogger running at 9 km hr along side a railway track is 260 m ahead of the engine of a 140 m long ...........

Quant (SSC) Problems on trains

A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?

25 sec

40 sec

38 sec

32 sec

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Explanation:

Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 x 5/18 = 10 m/sec.
Distance to be covered = 260 + 140 = 400 m.
Time taken = 400/10 = 40 sec.