send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Three pipes A, B and C are connected to a tank. Working alone, they require 10 hours, 20 hours and 30 hours respectively. After some time, A is closed and after another 2 hours, B is also closed. C works for another 14 hours so that the tank gets filled completely. Find the time (in hours) after which pipe A was closed.
1
1.5
2
3
Let the capacity of the tank be LCM (10, 20, 30) = 60 => Efficiency of pipe A = 60 / 10 = 6 units / hour => Efficiency of pipe B = 60 / 20 = 3 units / hour => Efficiency of pipe C = 60 / 30 = 2 units / hour Now, all three work for some time, say ‘t’ hours. So, B and C work for 2 more hours after ‘t’ hours and then, C works for another 14 hours. => Combined efficiency of pipe A, pipe B and pipe C = 11 units / hour => Combined efficiency of pipe B and pipe C = 5 units / hour So, we have 11 x t + 5 x 2 + 14 x 2 = 60 => 11 t + 10 + 28 = 60 => 11 t = 60 – 38 => 11 t = 22 => t = 2
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses