8 of the voters in an election did not cast their votes In this election there were only two n...........

Quantitative Aptitude ( CCS) Percentage

8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of the total votes defeated his rival by 1100 votes. The total number of voters in the election was

2100

23500

22000

27500

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Explanation:

Let total number of votes be x
Now, 1st candidate won 48% of total votes =48x/100
But, 8% from total voters don't give vote ; so votes gives
actually = x - 8x/100 = 92x/100
Now 2nd candidate must have got
92x/100 - 48x/100 = 44x/100, then
Now, 2nd candidate lost by 1st candidate by
1100 votes :-
48x/100 = 44x/100 + 1100
48x/100 - 44x/100 = 1100
4x/100 = 1100
x= 100/4 × 1100
x = 27,500 votes are polled.