A dog at point A goes in pursuit of a fox 40 m away The dog takes a leap of 2 m against 1 m long lea...........

Quantitative Aptitude ( CCS) Time & distance

A dog at point A goes in pursuit of a fox 40 m away. The dog takes a leap of 2 m against 1 m long leaps of fox. If the dog makes two leaps to the fox’s three, at what distance from A will the dog catch up with the fox?

100 m

120 m

140 m

160 m

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Explanation:

Distance per leap of dog = 2m
Distance per leap of fox = 1m
Dog takes 2 leaps and fox takes 3 leaps in the same time
Distance covered by dog in 2 leaps = 2×2= 4m
Distance covered by fox in 3 leaps = 1×3= 3m
In two leaps of dog distance reduces by =4m−3m=1m
No of leaps required by dog to cover the gap of 40 m =40×2= 80
Distance covered by dog in 80 leaps = 2×80=160 m
Hence the dog will catch up with the fox at 160 m from A.