send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
CIRCLE A circle is a set of points in a plane that are located at a same distance from the fixed point (the center of the circle). A chord of a circle is distance between two points on the circle. The largest chord is called diameter of the circle. Radius of a circle is half of the diameter. Circumference of a circle is the distance around the circle. If r is the radius of a circle, then the circumference is equal to 2πr, where π is approximately 3.14. The area of circle of radius r is equal to πr2.
In the above circle, O is the center of the circle and AB and CD are chords. AB is the diameter and OB is the radius. If OB = 5, then the perimeter of circle or circumference of circle is 2π(5) = 10π, and area of circle is π(5)2 = 100π.
A line that is perpendicular to the diameter or radius of circle at a point of contact on circle is called tangent. The line L is tangent to circle and radius OT is perpendicular to line L. If every vertex of a polygon lies on the circle, then the polygon is inscribed in the circle and the circle is called circumscribed. If every side of the polygon is tangent to the circle, then the polygon is circumscribed about a circle and the circle is inscribed in the polygon .
In the figure above, quadrilateral PQRS is inscribed in the circle and hexagon ABCDEF is circumscribed about the circle.
If a triangle is inscribed in the circle so that one of its sides is the diameter of circle, then the triangle is a right triangle. In the above circle, XZ is diameter and the measure of angle XYZ is 90°.
Some Important Properties of Circles:
Cyclic Quadrilaterals: A quadrilateral is said to be cyclic if opposite angles of the quadrilateral are supplementary and all of its vertices are on the circle. The points lying on a circle are called co cyclic.
The opposite angles of a cyclic quadrilateral are supplementary. Conversely, if the opposite angles of a quadrilateral are supplementary, then it is a cyclic quadrilateral.
An exterior angle of a cyclic quadrilateral is equal to the angle opposite to it
adjacent interior angle. ∠BCE = ∠DAC. For any cyclic quadrilateral, sum of product of two pairs of opposite sides equals the product of diagonals.
PQ × RS + QR × SP = PR × SQ. The area of a cyclic quadrilateral = √(s-a)(s-b)(s-c)(s-d) where s is the semi perimeter and a, b, c and d are sides of the quadrilateral. Area of a cyclic quadrilateral in which a circle can be inscribed =√a×b×c×d , where a, b, c and d are the sides of the quadrilateral.
Sectors of a Circle: The number of degrees of arc in a circle (or the number of degrees in a complete revolution) is 360.
In the above circle with center O, the length of arc RS is x/360 of the circumference of the circle; for example, if x = 60°, then arc RS has length 1/6 of the circumference of the circle. We can remember the following formulas:
Some Examples and solutions Example 1: What is the radius of a circle if its perimeter is numerically equal to thrice its area ? A. 2 B. 3 C. 2/3 D. 4 Explanation 2πr = 3πr2 ⇒ r = 2/3
Example 2: Find the radius of the circle if area of sector is 924 cm2 and angle at the center is 600. A. 42 B. 21 C. 22 D. 46 Explanation A= πr2 × 60/360 = 924 &⇒ r =42
Example 3: The difference between the circumference and area of a circle is 110 metres. Find its circumference. A. 44m B. 84m C. 30m D. 7m Explanation πr2 - 2Πr = 110 ⇒ r= 7 Circumference = 2×22/7×7 = 44
Example 4: When the radius of a circle is decreased by 100%, the area of the circle: A. decreases by 50% B. decreases by 100% C. increases by 100% D. decreases by 200% Explanation Since the radius of circle is reduced by 100%, the radius becomes 0. Therefore, area also decreases to 0. So, the area of the circle decreases by 100%.
Examples 5: A regular hexagon is inscribed in a circle of radius 10 cm. Find the area of the shaded portion. (× ≈ 3.14 ; √3 ≈ 1.73). A. 271 cm2 B. 54.5 cm2 C. 290 cm2 D. 75 cm2 Explanation Area of circle = π × 102 = 3.14 × 100 = 314 cm2. Area of regular hexagon = 6 × √3 / 4 × 10 × 10 = 259.5cm2. Area of shaded region = area of circle – area of hexagon = 314 – 259.5 = 54.5cm2.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
Access to prime resources
New Courses