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When a man looks from the foot and the top of a tower at the roof of a building, the angles of elevation and depression are of 270 and 630 respectively. If the height of the building is 40m, find the height of the tower. (tan 630=2)
400m
300m
250m
200m
Let AB is the tower and CD is the building of height 40m. In ΔACD, AC/DC = cot270 = cot(90-63) → AC/40 = tan630 = 2 → AC=80m Now DE=AC=80m In ΔBED, tan 630= BE/DE →2=BE/80 →BE=160m ∴Height of the tower = AE + EB = 40 + 160 = 200m
By: Amit Kumar ProfileResourcesReport error
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