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The angles of depression and elevation of the top of a building 15m high from the top and bottom of a tower are 600 and 300 respectively. Find the height of the tower
40m
50m
60m
80m
Let AB is the tower and CD is the building of height 15m ∴CD = AE = 15m In ΔACD, tan 300 = CD/AC ⇒ 1/√3 = 15/AC ⇒ AC = 15√3m ∴ DE = 15√3m Again in ΔBED, tan 600 = BE/ED ⇒ √3 = BE/15√3 ⇒ BE = 45m The height of the tower = AB = AE + EB = 15 + 45 = 60m
By: Amit Kumar ProfileResourcesReport error
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