The upper part of a tree is broken and the top touches the ground making an angle of 30 deg The dist...........

Quantitative Aptitude ( CCS) Trignometry

The upper part of a tree is broken and the top touches the ground making an angle of 30°. The distance of the point where the top touches the ground to the base of the tree is 72 m. What was the height of the tree?

124.7m

24.7m

156.7m

98.7m

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Explanation:

Let AC is the tree which broke at point B so that the top C touches the ground.
Here AC = 72 m
In ΔABC, tan30⁰ = AB/AC
Height And Distances Solved
→ 1/√3 = AB/72
→ AB = 72/√3 = 24√3m
Again in ΔABC, sin30⁰ = AB/AC
→ 1/2 = 24√3/BC
→ BC = 48√3m
Hence the length of the tree = AB + BC = 24√3+48√3 = 72√3 = 124.7m