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The angles of depression of the top and the bottom of a tree as seen from the top of a tower 90 meters high are 30? and 60? respectively. Find the height of the tree.
40m
45m
60m
75m
Let AB is the tower of height 90 m and CD is the tree. In ΔABC, tan600 =AB/AC → √3 = 90/AC → AC = 30√3 Hence DE = AC = 30√3m In ΔDEB, tan300 =BE/DE → 1/√3 = BE/30√3 →BE = 30m Hence CD = AE = 90 – 30 = 60m.
By: Amit Kumar ProfileResourcesReport error
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