From the top of a hill 120m high the angle of depression of top and bottom of a tower are 450 and 60...........

Quantitative Aptitude ( CCS) Trignometry

From the top of a hill 120m high, the angle of depression of top and bottom of a tower are 45⁰ and 60⁰ respectively, find the height of the tower.

40.83m

63.12m

77.14m

50.72m

छोटे Courses बड़े Results

Master Trignometry

Prepare through Micro-courses

Try Now

Explanation:

Let AB is the hill and CD is the tower.
In ΔABC, tan 60⁰ = AB/AC ⇒√3 = 120/AC
⇒ AC = 120/√3 = 40√3
Heights & Distance Probs
Now AC = DE = 40√3m
In ΔBED, tan 45⁰ = BE/ED ⇒ 1 ⇒ BE = ED
∴ BE = 40√3m
∴ AE = 120 - 40√3 = 120 – 69.28 = 50.72m
The height of the tower = 50.72m