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A man is standing on a corner of a square field. He observes that the angle of elevation of the top of a pole in the corner just diagonally opposite to this corner is 600. When he moves 100√2m from the corner along the same straight line (along the diagonal joining the two corners in question), he finds that the angle is 300. Find the area of the field.
100m2
2500m2
1600m2
1200m2
Let ABCD is the square field, the person is standing at A and the tower is CE. Here ∠CAE = 600 Let the person moves to the point F such that AF = 100√2m and ∠CFE = 300 Now in ΔACE tan 600 = CE/AC ⇒ CE = √3AC ----(1) In ΔECF, tan 300 = EC/CF Equating (1) & (2) we get ⇒ 3AC = 100√2m + AC ⇒ 2AC = 100√2m ⇒ AC = 50√2m Since AC is the diagonal of the square, so the side of the square is 50m. Hence the area of the square field is (50)2 = 2500m2.
By: Amit Kumar ProfileResourcesReport error
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