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A tower is surmounted by a vertical flag post of height 20m. At a point on the ground, the angle of elevation of the bottom and the top of the flag post are 300 and 600 respectively. Find the height of the tower.
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Let AB is the tower of height x m and BC is the flag post of height 20m. In ΔABD, tan 300 = AB/AD ⇒ 1/√3 = x/AD ⇒ AD = √3x ---(1) In ΔADC, tan 600 = AC/AD ⇒ √3 = (x + 20)/AD ⇒ AD = (x + 20)/√3 ---(2) From (1) & (2) we have (x + 20)/√3 = √3x ⇒ x + 20 = 3x ⇒ 2x = 20 ⇒ x = 10m ∴ The height of the tower is 10m.
By: Amit Kumar ProfileResourcesReport error
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