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A 10 m long flagstaff is fixed on the top of a tower on the horizontal plane. From a point on the ground, the angles of elevation of the top and bottom of the flagstaff are 600 and 450 respectively. Find the height of the tower.
5(√3 + 1)m
5(√3 + 3)m
10(√3 - 1)m
10(√3 + 1)m
Let AB is the tower of height x m and BC is the flagstaff of height 10 m. Let D be the point from where the angles of elevation are 450 and 600 such that ∠BDA = 450 and ∠CDA = 600 In ΔDAB, tan 450 = AB/AD ⇒ 1 = x/AD ⇒ AD = x In ΔDAC, tan 600 = AC/AD ⇒ √3 = (10+x)/x ⇒ √3x = 10+x ⇒ (√3-1)x = 10 ⇒ x = 10/(√3 - 1) = 10/(√3 - 1) x (√3 + 1)/(√3 + 1) ⇒ x = 5(√3 + 1)
By: Amit Kumar ProfileResourcesReport error
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