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Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B & C are open for one hour each alternatively, then tank will be full in
6 hours
6.5 hours
7 hours
7.5 hours
Ta= 12 hours
Tb= 15 hours
Tc= 20 hours
lcm ( total work ) = 60 units
=> Ea = 60/12 = 5 units per hours
Eb = 60/15 = 4 units per hours
Ea = 60/20 = 3 units per hours
on first hour ( A+B ) will work = 5+4 = 9 units
on second hour ( A+C ) will work = 5+3 = 8 units
so => 2 hour work = 17 units .
=> 6 hour work = 17 x 3 = 51 units
remaining work = 9 units .
so next work will be done by
(A+B) = 9 units
so, work will be completed in 7 hours
By: Gaurav Rana ProfileResourcesReport error
Yogesh Ambawta
No explanation
solution updated , kindly check.
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