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Evaluate the integral: ∫1-1 ex dx =
2(e-1 -1 )
2(e+1)
e−1
2(e−1)
To evaluate the integral \(\int_{-1}^{1} e^x \, dx\), consider the following steps:
- Step 1: Find the antiderivative of \(e^x\).
- The antiderivative of \(e^x\) is \(e^x + C\).
- Step 2: Evaluate the definite integral from -1 to 1.
- \(\left[e^x\right]_{-1}^{1} = e^1 - e^{-1}\).
- Simplifying gives: \(e - \frac{1}{e}\).
- Step 3: Multiply by 2 to account for symmetry in the interval from \(-1\) to \(1\).
Now, evaluate the options:
- Option 1: 2(e-1 - 1) - Incorrect.
- Option 2: 2(e + 1) - Incorrect.
- Option 3: \(e - 1\) - Incorrect.
- Option 4: 2(e - 1) - Correct, after simplification from e - (-1/e), we have \(2(e - 1)\).
This evaluation confirms that your answer, option 4, 2(e - 1), is indeed correct.
.
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