A shopkeeper buys 60 oranges at 10 for Rs72 and an equal number at 12 for Rs90 He spends Rs118 on th...........

Quantitative Aptitude (MTS) Profit and loss

A shopkeeper buys 60 oranges at 10 for Rs72, and an equal number at 12 for Rs90. He spends Rs118 on the transaction and sells

all the oranges that he buys. If there is a profit of 26% in the entire transaction, then what is the selling price of 32 oranges?

This questions was previously asked in

SSC MTS 27th October 2021 Shift-2

Rs336

Rs313.60

Rs316.80

Rs320

- The shopkeeper buys the first set of 60 oranges at 10 for Rs72. This means he spends Rs432 for these oranges.

- The second set of 60 oranges is bought at 12 for Rs90, costing him Rs450.

- Total cost for both sets = Rs432 + Rs450 = Rs882.

- He spends an additional Rs118, making the total transaction cost Rs882 + Rs118 = Rs1000.

- Given a profit of 26%, calculate the selling price: Total cost Rs1000 + 26% of Rs1000 = Rs1260.

- He sells 120 oranges, thus SP per orange = Rs1260 / 120 = Rs10.50.

- Selling price of 32 oranges = 32 * Rs10.50 = Rs336.

- Option 1: Rs336

- Option 2: Rs313.60

- Option 3: Rs316.80

- Option 4: Rs320

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