A hall is 18 m long and 12 m broad If the area of the floor is equal to the sum of the areas of the ...........

Quantitative Aptitude (MTS) Mensuration 3D

A hall is 18 m long and 12 m broad. If the area of the floor is equal to the sum of the areas of the four walls, the volume (in m³ )

of the hall is:

This questions was previously asked in

SSC MTS 22nd October 2021 Shift-3

876.2

777.6

576.4

675.5

- The dimensions of the hall are given as 18 meters in length and 12 meters in breadth.

- The formula for the area of the floor is: Length x Breadth = 18 m x 12 m = 216 m².

- We are told the area of the floor equals the sum of the areas of the four walls.

- The sum of the areas of the four walls can be calculated as:

$$ 2 \times \text{Height} \times (\text{Length} + \text{Breadth}) $$

$$ = 2h \times (18 + 12) $$

$$ = 60h $$

- Setting the area of the floor equal to the sum of the areas of the four walls gives us:

$$ 216 = 60h $$

- Solving for height ($ h $):

$$ h = \frac{216}{60} = 3.6 \text{ m} $$

- The volume of the hall can be calculated as: Length x Breadth x Height = 18 m x 12 m x 3.6 m = 777.6 m³.

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