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The average of 5 numbers, arranged in a row, is 309. The average of the first two of these numbers is 431 and the average of
the last two of these numbers is 231.5. What is the value of the number at the center of the row?
321
52
108
220
To solve the problem, let's break down the information:
- The average of 5 numbers is 309. Therefore, the sum of the 5 numbers is \(5 \times 309 = 1545\).
- The average of the first two numbers is 431. Thus, their sum is \(2 \times 431 = 862\).
- The average of the last two numbers is 231.5, which means their sum is \(2 \times 231.5 = 463\).
- Now, using these sums:
- Total sum of all five numbers: 1545
- Sum of the first two numbers: 862
- Sum of the last two numbers: 463
- The sum of the first two numbers and the last two numbers cover four of the five numbers.
- The number at the center of the row can be found by subtracting these sums:
- Center number = Total sum - (Sum of the first two + Sum of the last two)
- Center number = \(1545 - (862 + 463) = 1545 - 1325 = 220\)
- Correct Answer is Option:4, 220
By: santosh ProfileResourcesReport error
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