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In a housing society, the ratio of two-wheelers to four-wheelers is 11 : 9. Among the four-wheelers, one-fourth are petrol
vehicles and the remaining 81 are diesel vehicles. How many two-wheelers are there in this housing society?
121
88
132
99
- Let's analyze the problem with given ratios and information.
- Four-Wheelers:
- The problem states that three-fourths of the four-wheelers are diesel vehicles.
- There are 81 diesel vehicles, which means 81 is three-fourths of the four-wheelers.
- So, the total number of four-wheelers is 81 / (3/4) = 81 * 4 / 3 = 108.
- Two-Wheelers:
- The ratio of two-wheelers to four-wheelers is provided as 11:9.
- If four-wheelers total 108, then for the two-wheelers: (11/9) * 108 = 11 * 12 = 132.
- Correct Option:
- Among the options, 132 matches the calculated number of two-wheelers.
The correct answer is option:3 - 132. ""
By: santosh ProfileResourcesReport error
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