Explanation:

- We have a cylindrical rod with height equal to the radius of its base, so let the radius be 'r'. The height of the cylinder is also 'r'.

- Volume of the cylinder: \( V_{\text{cylinder}} = \pi r^2 \times r = \pi r^3 \).

- We need to find the number of spherical balls made from this volume.

- Radius of each spherical ball is half the radius of the cylinder's base, i.e., \( \frac{r}{2} \).

- Volume of one sphere:

$$

V_{\text{sphere}} = \frac{4}{3} \pi \left(\frac{r}{2}\right)^3 = \frac{4}{3} \pi \frac{r^3}{8} = \frac{\pi r^3}{6}

$$

- Number of spheres: Divide the volume of the cylinder by the volume of one sphere:

$$

\text{Number of balls} = \frac{\pi r^3}{\frac{\pi r^3}{6}} = 6

$$

- Correct Option: Option 2, 6

- Your Answer is Right: The calculations show that 6 spherical balls can be made.