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A man borrowed money and paid back in two equal annual instalments of Rs1,089, at 10% compound interest compounded
annually for 2 years. What was the sum (in Rs) borrowed?
2,178
2,090
1,890
1,800
Let’s break down the problem:
- The man pays Rs 1,089 twice (once each year) with 10% compound interest annually.
- Let the loan amount be P.
- The present value of instalments = 1,089/(1.10) + 1,089/(1.10)^2
Calculate:
- 1,089/1.10 = 990
- 1,089/1.21 ˜ 900
- Sum of present values = 990 + 900 = Rs 1,890
So, the initial loan amount was Rs 1,890.
Correct option:
Option 3: 1,890
- Option 1 (2,178) and Option 2 (2,090) are too high.
- Option 4 (1,800) is too low.
By: santosh ProfileResourcesReport error
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